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A body of mass 1 kg is thrown upwards with a velocity 20 m/s. It momentarily comes to rest after attaining a height of 18 m. How much energy is lost due to air friction? (g = 10 m/s²)
Options
(a) 30 J
(b) 40 J
(c) 10 J
(d) 20 J
Correct Answer:
20 J
Explanation:
When the body is thrown upwards. its K.E is converted into P.E. The loss of energy due to air friction is the difference of K.E and P.E
1/2 mv² – mgh = 1/2 x 1 x 400 – 1 x 18 x 10
= 200 – 180 = 20 J
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Topics: Work Energy and Power
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Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A microscope is having objective of focal length 1 cm and eye-piece of focal length 6 cm.
- The electric vector vibration of an electromagnetic wave is given by
- The decay constant of a radio isotope is λ. If A₁ and A₂ are its activities at time
- In Young’s double slit experiment, the locus of the point P lying in a plane
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Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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