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A body of mass 1 kg is thrown upwards with a velocity 20 m/s. It momentarily comes to rest after attaining a height of 18 m. How much energy is lost due to air friction? (g = 10 m/s²)
Options
(a) 30 J
(b) 40 J
(c) 10 J
(d) 20 J
Correct Answer:
20 J
Explanation:
When the body is thrown upwards. its K.E is converted into P.E. The loss of energy due to air friction is the difference of K.E and P.E
1/2 mv² – mgh = 1/2 x 1 x 400 – 1 x 18 x 10
= 200 – 180 = 20 J
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Topics: Work Energy and Power
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Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A spherical drop of capacitance 1μF is broken into eight drops of equal radius.
- At what angle should the two forces 2P and √2 P act,so that the resultant force is P√10?
- Two simple harmonic motions of angular frequency 100 and 1000 rad s⁻¹ have the same
- An electron in potentiometer experiences a force 2.4×10⁻¹⁹N. The length of potentiometer
- When ultraviolet rays are incident on metal plate, then photoelectric effect
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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