| ⇦ | 
| ⇨ |
A body of mass 1 kg is thrown upwards with a velocity 20 m/s. It momentarily comes to rest after attaining a height of 18 m. How much energy is lost due to air friction? (g = 10 m/s²)
Options
(a) 30 J
(b) 40 J
(c) 10 J
(d) 20 J
Correct Answer:
20 J
Explanation:
When the body is thrown upwards. its K.E is converted into P.E. The loss of energy due to air friction is the difference of K.E and P.E
1/2 mv² – mgh = 1/2 x 1 x 400 – 1 x 18 x 10
= 200 – 180 = 20 J
Related Questions: - A proton of mass 1.6×10⁻²⁷ kg goes round in a circular orbit of radius 0.10 m under
- A Si and a Ge diode has identical physical dimensions. The bandgap in Si is larger
- When a magnet is taken towards a coil, the induced e.m.f. depends on
- Two bodies of mass 0.25 kg each moving towards each other with velocity
- A body is thrown vertically upward in air when air resistance is taken into account
Topics: Work Energy and Power
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A proton of mass 1.6×10⁻²⁷ kg goes round in a circular orbit of radius 0.10 m under
- A Si and a Ge diode has identical physical dimensions. The bandgap in Si is larger
- When a magnet is taken towards a coil, the induced e.m.f. depends on
- Two bodies of mass 0.25 kg each moving towards each other with velocity
- A body is thrown vertically upward in air when air resistance is taken into account
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply