| ⇦ | 
| ⇨ |
A nucleus ᴢXᴬ emits an α- particle with velocity v. The recoil speed of the daughter nucleus is
Options
(a) A-4/4v
(b) 4v/A-4
(c) v
(d) v/4
Correct Answer:
4v/A-4
Explanation:
According to the question, zXᴬ → z-₂ Yᴬ⁻⁴ + ₂He⁴
Let the recoil speed of daughter nucleus is ʋ’. By the law of conservation of momentum, we have Initial momentum = Final momentum
0 = (A – 4)ʋ’ + 4ʋ
(A – 4) ʋ’ = -4ʋ ⇒ ʋ’ = 4ʋ / (A – 4)
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Topics: Radioactivity
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Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A body under the action of a force F⃗ = 6i⃗–8j⃗+10k⃗, acquires an accelerationof 1 m/s². The mass of this body must be
- Two closed pipes produce 10 beats per second when emitting their fundamental nodes.
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- A carnot engine working between 300 K and 600 K has a work output of 800J per cycle.
- Two capacitors of 10pF and 20pF are connected to 200V and 100V sources, respectively.
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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