| ⇦ |
| ⇨ |
A motorcycle moving with a velocity 72 kmh⁻¹ on a flat road takes a turn on the road at a point where the radius of curvature of the road is 20 m,the acceleration due to gravity is 10 ms⁻².In order to avoid skidding, he must not bent with respect to the vertical plane by an angle greater than
Options
(a) θ = tan⁻¹(2)
(b) θ = tan⁻¹(6)
(c) θ = tan⁻¹(4)
(d) θ = tan⁻¹(25.92)
Correct Answer:
θ = tan⁻¹(2)
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Which of the following is a vector quantity?
- The moment of inertia of a rod about an axis through its centre and perpendicular
- At what temperature will the rms speed of air molecules be double that of NTP?
- The time of reverberation of a room A is one second. What will be the time (in seconds)
- The current in the coil of inductance 5H decreases at the rate of 2 A/s
Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following is a vector quantity?
- The moment of inertia of a rod about an axis through its centre and perpendicular
- At what temperature will the rms speed of air molecules be double that of NTP?
- The time of reverberation of a room A is one second. What will be the time (in seconds)
- The current in the coil of inductance 5H decreases at the rate of 2 A/s
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply