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A motorcycle moving with a velocity 72 kmh⁻¹ on a flat road takes a turn on the road at a point where the radius of curvature of the road is 20 m,the acceleration due to gravity is 10 ms⁻².In order to avoid skidding, he must not bent with respect to the vertical plane by an angle greater than
Options
(a) θ = tan⁻¹(2)
(b) θ = tan⁻¹(6)
(c) θ = tan⁻¹(4)
(d) θ = tan⁻¹(25.92)
Correct Answer:
θ = tan⁻¹(2)
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Two bodies A(of mass 1kg) and B(of mass 3 kg) are dropped from heights of 16m and 25m
- When a mass m is attached to a spring, it normally extends by 0.2 m.
- The work function for metals A,B abd C are respectively 1.92 eV,2.0 eV and 5 eV.
- The charge flowing through a resistance R varies with time t as Q=at-bt²,
- A block of mass 5 kg is moving horizontally at a speed of 1.5 m/s. A perpendicular force
Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two bodies A(of mass 1kg) and B(of mass 3 kg) are dropped from heights of 16m and 25m
- When a mass m is attached to a spring, it normally extends by 0.2 m.
- The work function for metals A,B abd C are respectively 1.92 eV,2.0 eV and 5 eV.
- The charge flowing through a resistance R varies with time t as Q=at-bt²,
- A block of mass 5 kg is moving horizontally at a speed of 1.5 m/s. A perpendicular force
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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