⇦ | ⇨ |
A meter stick of mass 400 g is pivoted at one end and displaced through an angle 60°. The increase in its potential energy is
Options
(a) 2 J
(b) 3 J
(c) 0 J
(d) 1 J
Correct Answer:
1 J
Explanation:
Change in potential energy = mg/(1/2) (1-cosθ)
Given: mass = 400g = 0.4 kg and angle = 60°
Therefore, ∆U = 0.4 × 10 × (1/2) × (1-cos 60°) = 1 J.
Related Questions: - Two coherent sources of intensity ratio α interfere. In interference pattern,
- If two soap bubbles of different radii are connected by a tube
- The potential energy of a weightless spring compressed by a distance D is proportional
- The magnetic field in a certain region of space is given by B =8.35×10⁻² Î T.
- A satellite A of mass m is at a distance r from the centre of earth. Another satellite
Topics: Motion of system of Particles and Rigid Body
(73)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two coherent sources of intensity ratio α interfere. In interference pattern,
- If two soap bubbles of different radii are connected by a tube
- The potential energy of a weightless spring compressed by a distance D is proportional
- The magnetic field in a certain region of space is given by B =8.35×10⁻² Î T.
- A satellite A of mass m is at a distance r from the centre of earth. Another satellite
Topics: Motion of system of Particles and Rigid Body (73)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply