| ⇦ | 
| ⇨ |
A metal conductor of length 1m rotates vertically about one of its ends at angular velocity 5 radian per second. If the horizontal component of earth’s magnetic field is 0.2×10⁻⁴ T, then the e.m.f. developed between the two ends of the conductor is
Options
(a) 5 μV
(b) 50 mV
(c) 5 mV
(d) 50 μV
Correct Answer:
50 mV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The time period of bar magnet is doubled when magnetic field is reduced
- The displacement of an object attached to a spring and executing simple harmonic
- In a uniform circular motion,
- The mean radius of the earth is R, its angular speed on its own axis is ?
- If an electron and a proton have the same de-Broglie wavelength, then the kinetic
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The time period of bar magnet is doubled when magnetic field is reduced
- The displacement of an object attached to a spring and executing simple harmonic
- In a uniform circular motion,
- The mean radius of the earth is R, its angular speed on its own axis is ?
- If an electron and a proton have the same de-Broglie wavelength, then the kinetic
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply