⇦ | ⇨ |
A metal conductor of length 1m rotates vertically about one of its ends at angular velocity 5 radian per second. If the horizontal component of earth’s magnetic field is 0.2×10⁻⁴ T, then the e.m.f. developed between the two ends of the conductor is
Options
(a) 5 μV
(b) 50 mV
(c) 5 mV
(d) 50 μV
Correct Answer:
50 mV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - When germanium is doped with phosphorus what type of semiconductor is produced?
- The resistance in the two arms of the meter bridge are 5Ω and RΩ, respectively
- The electric potential at a point (x,y,z) is given by V = – x²y – xz³ + 4.
- A particle of mass 100 g is thrown vertically upwards with a speed of 5 m/s. The work
- A battery of emf 10 V and internal resistance 3 ohm is connected to a resistor.
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When germanium is doped with phosphorus what type of semiconductor is produced?
- The resistance in the two arms of the meter bridge are 5Ω and RΩ, respectively
- The electric potential at a point (x,y,z) is given by V = – x²y – xz³ + 4.
- A particle of mass 100 g is thrown vertically upwards with a speed of 5 m/s. The work
- A battery of emf 10 V and internal resistance 3 ohm is connected to a resistor.
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply