| ⇦ | 
| ⇨ |
A mass of 2.0 kg is put on a flat plan attached to a vertical spring fixed on the ground as shown in the figure. The mass of the spring and the pan is negligible. When pressed slightly and released the mass executes a simple harmonic motion. The spring constant is 200 N/m. What should be the minimum amplitude of the motion so that the mass gets detached from the pan (take g=10 m/s²)
Options
(a) 10.0 cm
(b) Any value less than 12.0 cm
(c) 4.0 CM
(d) 8.0 CM
Correct Answer:
10.0 cm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - What is the voltage gain in a common-emiiter amplifier, when input resistance is 4 Ω
- Heat is not being exchanged in a body. If its internal energy is increased, then
- Length of a string tied to two rigid supports is 40 cm. Maximum length
- Two spherical nuclei have mass numbers 216 and 64 with their radii R₁ and R₂,
- Which one of the following bonds produces a solid that reflects light in the visible region
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- What is the voltage gain in a common-emiiter amplifier, when input resistance is 4 Ω
- Heat is not being exchanged in a body. If its internal energy is increased, then
- Length of a string tied to two rigid supports is 40 cm. Maximum length
- Two spherical nuclei have mass numbers 216 and 64 with their radii R₁ and R₂,
- Which one of the following bonds produces a solid that reflects light in the visible region
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply