⇦ | ⇨ |
A marble block of mass 2 kg lying on ice when given a velocity of 6 m/s is stopped by friction in 10 sec. Then the coefficient of friction is
Options
(a) 0.01
(b) 0.02
(c) 0.03
(d) 0.06
Correct Answer:
0.06
Explanation:
From equation of motion, v = u – at
⇒ o = u – μgt
⇒ μ = u/gt
= 6/(10×10)
= 0.06
Related Questions: - The material suitable for making electromagnets should have
- The resistance in the two arms of the meter bridge are 5Ω and RΩ, respectively
- A radioactive sample S₁ having an activity of 5 μCi has twice the number of nuclei
- Complete the reaction: ₀n¹+ ₉₂U²³⁵→₅₆Ba¹⁴⁴+……..+3n
- A tuning fork A produces 4 beats per second with another tuning fork B of frequency
Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The material suitable for making electromagnets should have
- The resistance in the two arms of the meter bridge are 5Ω and RΩ, respectively
- A radioactive sample S₁ having an activity of 5 μCi has twice the number of nuclei
- Complete the reaction: ₀n¹+ ₉₂U²³⁵→₅₆Ba¹⁴⁴+……..+3n
- A tuning fork A produces 4 beats per second with another tuning fork B of frequency
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply