⇦ | ![]() | ⇨ |
A magnetic force acting on a charged particle of charge -2µC in a magnetic field of 2T acting in y direction, when the particle velocity is (2i + 3j) x 10⁶ m/s, is
Options
(a) 4 N in z direction
(b) 8 N in y direction
(c) 8 N in z direction
(d) 8 N in -z direction
Correct Answer:
8 N in -z direction
Explanation:
The magnetic force acting on the charged particle is given by F⃗ = q(v⃗ x B⃗)
= (-2 x 10⁻⁶) [ { 2i + 3j) x 10⁶} x (2i) ]
= – 4 (2k) = – 8k
Force is of 8N along -z-axis.
Related Questions:
- The minimum wavelength of X-rays produced in a Collidge tube operated
- For the radioactive nuclei that undergo either α or β decay, which one
- If a magnet is suspended at an angle 30⁰ to the magnetic meridian, the dip needle
- An engine is moving towards a wall with a velocity 50 ms⁻¹ emits a note of 1.2 kHz.
- A radioactive element forms its own isotope after 3 consecutive disintegrations.
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply