| ⇦ |
| ⇨ |
A light whose frequency is equal to 6.0 x 10¹⁴ Hz is incident on a metal whose work function is 2 eV. (h= 6.63 x 10⁻³⁴ Js, 1 ev = 1.6 x 10⁻¹⁹ J). The maximum energy of the electron emitted will be
Options
(a) 2.49 eV
(b) 4.49 eV
(c) 0.49 eV
(d) 5.49 eV
Correct Answer:
0.49 eV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The frequency of light ray having the wavelength 3000Å is
- The half life of radium is about 1600 year. Of 100 gram of radium existing now
- The dual nature of light is exhibited by
- When light of wavelength 300 nm falls on a photoelectric emitter,
- Young’s modulus of the material of a wire is 18×10¹¹ dyne cm⁻².its value in SI is
Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The frequency of light ray having the wavelength 3000Å is
- The half life of radium is about 1600 year. Of 100 gram of radium existing now
- The dual nature of light is exhibited by
- When light of wavelength 300 nm falls on a photoelectric emitter,
- Young’s modulus of the material of a wire is 18×10¹¹ dyne cm⁻².its value in SI is
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply