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A light whose frequency is equal to 6.0 x 10¹⁴ Hz is incident on a metal whose work function is 2 eV. (h= 6.63 x 10⁻³⁴ Js, 1 ev = 1.6 x 10⁻¹⁹ J). The maximum energy of the electron emitted will be
Options
(a) 2.49 eV
(b) 4.49 eV
(c) 0.49 eV
(d) 5.49 eV
Correct Answer:
0.49 eV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An ideal heat engine works between temperature T₁=500 K and T₂=375 K.
- Pure Si at 500 K has equal number of electron (nₑ) and hole (nₕ) concentrations
- The ratio of speed of an electron in ground state in Bohr’s first orbit of hydrogen atom
- A body of mass 2 kg travels according to the law x(t)=pt+qt²+rt³
- The identical loops of copper and aluminium are moving with the same speed
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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