⇦ | ⇨ |
A light whose frequency is equal to 6.0 x 10¹⁴ Hz is incident on a metal whose work function is 2 eV. (h= 6.63 x 10⁻³⁴ Js, 1 ev = 1.6 x 10⁻¹⁹ J). The maximum energy of the electron emitted will be
Options
(a) 2.49 eV
(b) 4.49 eV
(c) 0.49 eV
(d) 5.49 eV
Correct Answer:
0.49 eV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - 3 persons are initially at the 3 corners of an equilateral triangle
- A small object of uniform density rolls up a curved surface with an initial velocity
- A vibrating string of certain length l under a tension T resonates with a mode
- A short bar magnet of magnetic moment 0.4 JT⁻¹ is placed in a uniform magnetic field
- The radius of curvature of the convex face of a plano-convex lens is 12 cm
Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- 3 persons are initially at the 3 corners of an equilateral triangle
- A small object of uniform density rolls up a curved surface with an initial velocity
- A vibrating string of certain length l under a tension T resonates with a mode
- A short bar magnet of magnetic moment 0.4 JT⁻¹ is placed in a uniform magnetic field
- The radius of curvature of the convex face of a plano-convex lens is 12 cm
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply