| ⇦ | 
| ⇨ |
A light whose frequency is equal to 6.0 x 10¹⁴ Hz is incident on a metal whose work function is 2 eV. (h= 6.63 x 10⁻³⁴ Js, 1 ev = 1.6 x 10⁻¹⁹ J). The maximum energy of the electron emitted will be
Options
(a) 2.49 eV
(b) 4.49 eV
(c) 0.49 eV
(d) 5.49 eV
Correct Answer:
0.49 eV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - In Bohr model of hydrogen atom, the force on the electron depends on the principal
- Which of the following parameters does not characterize the thermodynamic state
- An air core coil and an electric bulb are connected in series with an AC source.
- Two simple harmonic motions of angular frequency 100 and 1000 rad s⁻¹ have the same
- The potential energy of a 1 kg particle free to move along the x-axis is given by
Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In Bohr model of hydrogen atom, the force on the electron depends on the principal
- Which of the following parameters does not characterize the thermodynamic state
- An air core coil and an electric bulb are connected in series with an AC source.
- Two simple harmonic motions of angular frequency 100 and 1000 rad s⁻¹ have the same
- The potential energy of a 1 kg particle free to move along the x-axis is given by
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply