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A light whose frequency is equal to 6.0 x 10¹⁴ Hz is incident on a metal whose work function is 2 eV. (h= 6.63 x 10⁻³⁴ Js, 1 ev = 1.6 x 10⁻¹⁹ J). The maximum energy of the electron emitted will be
Options
(a) 2.49 eV
(b) 4.49 eV
(c) 0.49 eV
(d) 5.49 eV
Correct Answer:
0.49 eV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Alternating current cannot be measured by D.C Ammeter because
- The escape velocity of a body on an imaginary planet which is thrice the radius
- What is the time taken by moon light to reach earth?
- ₆C¹⁴ absorbs an energitic neutron and emits beta particles. The resulting nucleus is
- A stone of mass 1kg is tied to a string 4m long and is rotated at constant speed
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Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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