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A light whose frequency is equal to 6.0 x 10¹⁴ Hz is incident on a metal whose work function is 2 eV. (h= 6.63 x 10⁻³⁴ Js, 1 ev = 1.6 x 10⁻¹⁹ J). The maximum energy of the electron emitted will be
Options
(a) 2.49 eV
(b) 4.49 eV
(c) 0.49 eV
(d) 5.49 eV
Correct Answer:
0.49 eV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The binding energy per nucleon in deuterium and helium nuclei are 1.1 MeV and 7.0 MeV
- A particle moves a distance x in time but according to equation x=(t+5)⁻¹
- A luminous object is seperated from a screen by distance d. A convex lens
- A comb run through one’s dry hair attracts small bits of paper. This is due to
- A certain mass of Hydrogen is changed to Helium by the process of fusion
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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