| ⇦ | 
| ⇨ |
A light of wavelength 5000Å falls on a sensitive plate with photoelectric work function 1.90 eV. Kinetic energy of the emitted photoelectrons will be (given, h=6.62×10⁻³⁴ Js)
Options
(a) 0.1 eV
(b) 2 eV
(c) 0.58 eV
(d) 1.581 eV
Correct Answer:
0.58 eV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The energy of the em waves is of the order of 15 keV. To which part of the spectrum
- A boy standing at top of a tower of 20 m height drops a stone
- The coherence of two light sources means that the light waves emitted have
- A beam of light of λ=600 nm from a distant source falls on a single slit 1 mm wide
- The ratio of specific heats Cp/Cv=γ in terms of degrees of freedom (n) is given by
Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The energy of the em waves is of the order of 15 keV. To which part of the spectrum
- A boy standing at top of a tower of 20 m height drops a stone
- The coherence of two light sources means that the light waves emitted have
- A beam of light of λ=600 nm from a distant source falls on a single slit 1 mm wide
- The ratio of specific heats Cp/Cv=γ in terms of degrees of freedom (n) is given by
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply