| ⇦ | 
| ⇨ |
A hollow sphere of radius 0.1m has a charge of 5×10⁻⁸C. The potential at a distance of 5cm from the centre of the sphere is
(1/4πε₀=9×10⁹NM²C⁻²)
Options
(a) 4000V
(b) 4500V
(c) 5000V
(d) 6000V
Correct Answer:
4500V
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The two ends of a rod of length L and a uniform cross-sectional area
- A block of mass 5 kg is moving horizontally at a speed of 1.5 m/s. A perpendicular force
- If wavelength of a wave is λ=6000 Å, then wave number will be
- The electirc field in a certain region is acting radially outward and is given by E=Ar.
- A spring balance is attached to the ceiling of a lift.A man hangs his bag on the spring
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The two ends of a rod of length L and a uniform cross-sectional area
- A block of mass 5 kg is moving horizontally at a speed of 1.5 m/s. A perpendicular force
- If wavelength of a wave is λ=6000 Å, then wave number will be
- The electirc field in a certain region is acting radially outward and is given by E=Ar.
- A spring balance is attached to the ceiling of a lift.A man hangs his bag on the spring
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Given,R=0.1m,q=5×10^-8c
V=kq/R=>V=9×10^9×5×10^-8/0.1=>V=45×10/0.1=>V=450×10=>V=4500v