⇦ | ![]() | ⇨ |
A hollow sphere of radius 0.1m has a charge of 5×10⁻⁸C. The potential at a distance of 5cm from the centre of the sphere is
(1/4πε₀=9×10⁹NM²C⁻²)
Options
(a) 4000V
(b) 4500V
(c) 5000V
(d) 6000V
Correct Answer:
4500V
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions:
- Magnetic susceptibility of a material is given as
- In Young’s double slit experiment, the slit seperation is 1 mm and the screen
- The input resistance of a silicon transistor is 100 W. Base current is changed
- Following figures show the arrangement of bar magnets in different configurations
- An alternating emf given by equation
e=300 sin[(100 π)t] V
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Given,R=0.1m,q=5×10^-8c
V=kq/R=>V=9×10^9×5×10^-8/0.1=>V=45×10/0.1=>V=450×10=>V=4500v