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A hemispherical bowl of radius R is rotating about its axis of symmetry which is kept vertical.A small ball kept in the bowl rotates with the bowl without sliiping on its surface.If the surface of the bowl is smooth and the angle made by the radius through the ball with the vertical is α.Find the angular speed at which the bowl is rotating.
Options
(a) √(g / R sinα)
(b) √(g / R cosα)
(c) g√(1 / R cosα)
(d) g√(1 / R sinα)
Correct Answer:
√(g / R cosα)
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Energy bands in solids are a consequence of
- A galvanometer has a resistance 50Ω. A resistance of 5Ω is connected parallel to it.
- The two ends of a rod of length L and a uniform cross-sectional area
- Calculate power output of ₉₂²³⁵U reactor, if it takes 30 days to use up 2 kg of fuel,
- The angular velocity of a wheel increases from 100 rps to 300 rps in 10 seconds.
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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