| ⇦ |
| ⇨ |
A hemispherical bowl of radius R is rotating about its axis of symmetry which is kept vertical.A small ball kept in the bowl rotates with the bowl without sliiping on its surface.If the surface of the bowl is smooth and the angle made by the radius through the ball with the vertical is α.Find the angular speed at which the bowl is rotating.
Options
(a) √(g / R sinα)
(b) √(g / R cosα)
(c) g√(1 / R cosα)
(d) g√(1 / R sinα)
Correct Answer:
√(g / R cosα)
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The motion of a particle along a straight line is described by equation
- The angular velocity of second’s hand of a watch is
- The frequencies of X-rays,γ-rays and ultraviolet rays are respectively p,q and r
- The purpose of using heavy water in nuclear reactor is
- Consider two particles of different masses. In which of the following situations
Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The motion of a particle along a straight line is described by equation
- The angular velocity of second’s hand of a watch is
- The frequencies of X-rays,γ-rays and ultraviolet rays are respectively p,q and r
- The purpose of using heavy water in nuclear reactor is
- Consider two particles of different masses. In which of the following situations
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply