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In Wheatstone bridge, three resistors P,Q and R are conncected in three arms in order and 4th arm of resistance s, is formed by two resistors s₁ and s₂ connected in parallel. The condition for bridge to be balanced is, P/Q
Options
(a) R(s₁+s₂)/s₁s₂
(b) s₁s₂/R(s₁+s₂)
(c) R(s₁s₂)/(s₁+s₂)
(d) (s₁+s₂)R(s₁s₂)
Correct Answer:
R(s₁+s₂)/s₁s₂
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Electric field intensity at a point in between two parallel sheets due to like
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Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Electric field intensity at a point in between two parallel sheets due to like
- A capacitor of 10 µF charged upto 250 volt is connected in parallel with another
- The magnetic flux linked with a circuit of resistance 100Ω increases from 10 to 60 Wb.
- Two cities are 150 km apart. Electric power is sent from one city to another city
- A block of mass m1 rests on a horizontal table. A light string connected
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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