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A hemispherical bowl of radius R is rotating about its axis of symmetry which is kept vertical.A small ball kept in the bowl rotates with the bowl without sliiping on its surface.If the surface of the bowl is smooth and the angle made by the radius through the ball with the vertical is α.Find the angular speed at which the bowl is rotating.
Options
(a) √(g / R sinα)
(b) √(g / R cosα)
(c) g√(1 / R cosα)
(d) g√(1 / R sinα)
Correct Answer:
√(g / R cosα)
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In vacuum, to travel distance d, light takes time t and in medium to travel distance
- If oxygen has root mean square velocity of C m/s, then root mean square velocity of H
- A proton of mass 1.6×10⁻²⁷ kg goes round in a circular orbit of radius 0.10 m under
- Alternating current is transmitted to distant places at
- What is the Q-value of the reaction? ¹H+⁷Li→⁴He+⁴He
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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