| ⇦ | 
| ⇨ |
A heavy small sized sphere is suspended by a string of length l.The sphere rotates uniformly in a horizontal circle with the string making an angle θ with the vertical.Then, the time-period of this conical pendulum is
Options
(a) t = 2?￢ﾈﾚ(l/g)
(b) t = 2?￢ﾈﾚ(lsinθ/g)
(c) t = 2?￢ﾈﾚ(lcosθ/g)
(d) t = 2?￢ﾈﾚ(l/g cosθ)
Correct Answer:
t = 2?￢ﾈﾚ(lcosθ/g)
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The instantaneous values of alternating current and voltages in a circuit are given as
- A spring of spring constant 5 x 10³ Nm⁻¹ is streched intially by 5 cm from
- A coil of inductive reactance 31 Ω has a resistance of 8 Ω. It is placed in series
- A cord is wound round the circumference of wheel of radius
- A galvanometer acting as a voltmeter will have
Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The instantaneous values of alternating current and voltages in a circuit are given as
- A spring of spring constant 5 x 10³ Nm⁻¹ is streched intially by 5 cm from
- A coil of inductive reactance 31 Ω has a resistance of 8 Ω. It is placed in series
- A cord is wound round the circumference of wheel of radius
- A galvanometer acting as a voltmeter will have
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply