| ⇦ | 
| ⇨ |
A heavy small sized sphere is suspended by a string of length l.The sphere rotates uniformly in a horizontal circle with the string making an angle θ with the vertical.Then, the time-period of this conical pendulum is
Options
(a) t = 2?￢ﾈﾚ(l/g)
(b) t = 2?￢ﾈﾚ(lsinθ/g)
(c) t = 2?￢ﾈﾚ(lcosθ/g)
(d) t = 2?￢ﾈﾚ(l/g cosθ)
Correct Answer:
t = 2?￢ﾈﾚ(lcosθ/g)
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Which one of the following statement is FALSE ?
- The radii of circular orbits of two satellites A and B of the earth, are 4R and R
- A nucleus disintegrates into two nuclear parts which have their velocities in the ratio
- A wire of length 1 m is moving at a speed of 2 ms⁻¹ perpendicular to its length
- A uniform wire of resistance 9Ω is joined end-to-end to form a circle. Then
Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which one of the following statement is FALSE ?
- The radii of circular orbits of two satellites A and B of the earth, are 4R and R
- A nucleus disintegrates into two nuclear parts which have their velocities in the ratio
- A wire of length 1 m is moving at a speed of 2 ms⁻¹ perpendicular to its length
- A uniform wire of resistance 9Ω is joined end-to-end to form a circle. Then
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply