| ⇦ | 
| ⇨ |
A heavy small sized sphere is suspended by a string of length l.The sphere rotates uniformly in a horizontal circle with the string making an angle θ with the vertical.Then, the time-period of this conical pendulum is
Options
(a) t = 2?￢ﾈﾚ(l/g)
(b) t = 2?￢ﾈﾚ(lsinθ/g)
(c) t = 2?￢ﾈﾚ(lcosθ/g)
(d) t = 2?￢ﾈﾚ(l/g cosθ)
Correct Answer:
t = 2?￢ﾈﾚ(lcosθ/g)
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The radius of orbit of a planet is two times that of the earth. The time period
- In an a.c circuit the e.m.f. (e) and the current (i) at any instant are given
- An object is placed at a distance of 10 cm from a co-axial combination of two lenses
- Two coherent sources of different intensities send waves which interfere.
- The additional energy that should be given to an electron to reduce its de-Broglie
Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The radius of orbit of a planet is two times that of the earth. The time period
- In an a.c circuit the e.m.f. (e) and the current (i) at any instant are given
- An object is placed at a distance of 10 cm from a co-axial combination of two lenses
- Two coherent sources of different intensities send waves which interfere.
- The additional energy that should be given to an electron to reduce its de-Broglie
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply