⇦ | ⇨ |
A Gaussian surface in the cylinder of cross-section πa² and length L is immersed in a uniform electric field E with the cylinder axis parallel to the field.The flux ? of the electric field through the closed surface is
Options
(a) 2πa²E
(b) πa²EL
(c) πa²(2+L)E
(d) zero
Correct Answer:
zero
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Two capacitors of capacitances 2 μF and 3 μF are joined in series.
- The intensity of magnetisation of a bar magnet is 5×10⁴ Am⁻¹. The magnetic length
- If the sodium light in Young’s double slit experiment is replaced by red light
- Maximum range for a projectile motion is given as R. The maximum height will be
- The velocity of radio-waves is 3×10⁵ km/s. The frequency corresponding to wavelength
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two capacitors of capacitances 2 μF and 3 μF are joined in series.
- The intensity of magnetisation of a bar magnet is 5×10⁴ Am⁻¹. The magnetic length
- If the sodium light in Young’s double slit experiment is replaced by red light
- Maximum range for a projectile motion is given as R. The maximum height will be
- The velocity of radio-waves is 3×10⁵ km/s. The frequency corresponding to wavelength
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply