| ⇦ | 
| ⇨ |
A force acts on a 3.0 g particle in such a way that the position of the particle as a function of time is given by x = 3t – 4t² + t³ , where x is in metre and t is in second. The work done during the first 4 s is
Options
(a) 570 mj
(b) 450 mj
(c) 490 mj
(d) 530 mj
Correct Answer:
530 mj
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - If the value of potential in an A.C circuit is 10 V, the peak value of potential is
- The direction of magnetic line of force of a bar magnet is
- In a double slit experiment, the two slits are 1mm apart and the screen is placed 1 m
- Light emitted during the de excitation of electron from n=3 to n=2, when incident
- A metal wire of circular cross-section has a resistance R₁. The wire is now stretched
Topics: Work Energy and Power
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If the value of potential in an A.C circuit is 10 V, the peak value of potential is
- The direction of magnetic line of force of a bar magnet is
- In a double slit experiment, the two slits are 1mm apart and the screen is placed 1 m
- Light emitted during the de excitation of electron from n=3 to n=2, when incident
- A metal wire of circular cross-section has a resistance R₁. The wire is now stretched
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply