| ⇦ | 
| ⇨ |
A force acts on a 3.0 g particle in such a way that the position of the particle as a function of time is given by x = 3t – 4t² + t³ , where x is in metre and t is in second. The work done during the first 4 s is
Options
(a) 570 mj
(b) 450 mj
(c) 490 mj
(d) 530 mj
Correct Answer:
530 mj
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The ratio of amplitude of magnetic field to the amplitude of electric field for
- One milligram of matter on convertion into energy will give
- Two identical circular coils A and B are kept on a horizontal tube
- Two points are located at a distance of 10 m and 15 m from the source of oscillation
- Which one of the following statements is true, if half-life of a radioactive substance
Topics: Work Energy and Power
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The ratio of amplitude of magnetic field to the amplitude of electric field for
- One milligram of matter on convertion into energy will give
- Two identical circular coils A and B are kept on a horizontal tube
- Two points are located at a distance of 10 m and 15 m from the source of oscillation
- Which one of the following statements is true, if half-life of a radioactive substance
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply