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A common emitter amplifier is designed with n-p-n transistor (α=0.99). The input impedence is 1kΩ and load is 10kΩ. The voltage gain will be
Options
(a) 9900
(b) 99
(c) 9.9
(d) 990
Correct Answer:
990
Explanation:
Voltage gain = β × Resistance gain
β = α/(1-α) = 0.99 / (1-0.99) = 99
Resistance gain = (10 × 10³) = 10
Voltage gain = 99 × 10 = 990
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Topics: Electronic Devices
(124)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A galvanometer coil has a resistance of 15 ohm and gives full scale deflection
- A radioactive nucleus of mass M emits a photon of frequency v and the nucleus recoils.
- Consider 3rd orbit of He⁺(helium), using non-relativistic approach, the speed
- The displacement of a particle along the x-axis is given by x = a sin² ?t
- When a current of (2.5±0.5) A flows through a wire, it develops a potential difference
Topics: Electronic Devices (124)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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