| ⇦ |
| ⇨ |
A common emitter amplifier is designed with n-p-n transistor (α=0.99). The input impedence is 1kΩ and load is 10kΩ. The voltage gain will be
Options
(a) 9900
(b) 99
(c) 9.9
(d) 990
Correct Answer:
990
Explanation:
Voltage gain = β × Resistance gain
β = α/(1-α) = 0.99 / (1-0.99) = 99
Resistance gain = (10 × 10³) = 10
Voltage gain = 99 × 10 = 990
Related Questions: - The difference in the variation of resistance with temperature in a metal
- The maximum wavelength of radiations emitted at 900K is 4 µm. What will be the maximum
- Curie temperature above which
- A string in musical instrument is 50 cm long and its fundamental frequency is 800 Hz.
- The kinetic energy of an electron in the first excited state is
Topics: Electronic Devices
(124)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The difference in the variation of resistance with temperature in a metal
- The maximum wavelength of radiations emitted at 900K is 4 µm. What will be the maximum
- Curie temperature above which
- A string in musical instrument is 50 cm long and its fundamental frequency is 800 Hz.
- The kinetic energy of an electron in the first excited state is
Topics: Electronic Devices (124)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply