| ⇦ | 
| ⇨ |
A common emitter amplifier is designed with n-p-n transistor (α=0.99). The input impedence is 1kΩ and load is 10kΩ. The voltage gain will be
Options
(a) 9900
(b) 99
(c) 9.9
(d) 990
Correct Answer:
990
Explanation:
Voltage gain = β × Resistance gain
β = α/(1-α) = 0.99 / (1-0.99) = 99
Resistance gain = (10 × 10³) = 10
Voltage gain = 99 × 10 = 990
Related Questions: - In Young’s double slit experiment with sodium vapour lamp of wavelength
- Two pendulums A and B are oscillating simultaneously with time period
- If the focal length of a concave mirror is 50 cm, then where should the object
- If the temperature of the sun were to increase from T to 2T and its radius from R and 2R
- The drive shaft of an automobile rotates at 3600 rpm and transmits 80 HP
Topics: Electronic Devices
(124)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In Young’s double slit experiment with sodium vapour lamp of wavelength
- Two pendulums A and B are oscillating simultaneously with time period
- If the focal length of a concave mirror is 50 cm, then where should the object
- If the temperature of the sun were to increase from T to 2T and its radius from R and 2R
- The drive shaft of an automobile rotates at 3600 rpm and transmits 80 HP
Topics: Electronic Devices (124)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply