| ⇦ | 
| ⇨ |
A common emitter amplifier is designed with n-p-n transistor (α=0.99). The input impedence is 1kΩ and load is 10kΩ. The voltage gain will be
Options
(a) 9900
(b) 99
(c) 9.9
(d) 990
Correct Answer:
990
Explanation:
Voltage gain = β × Resistance gain
β = α/(1-α) = 0.99 / (1-0.99) = 99
Resistance gain = (10 × 10³) = 10
Voltage gain = 99 × 10 = 990
Related Questions: - Two positive ions, each carrying a charge q, are separated by a distance d
- A particle moves along the x-axis from x=0 to x=5 m under the influence of a force
- An ideal heat engine works between temperature T₁=500 K and T₂=375 K.
- A bar magnet of magnetic moment M is placed at right angles to a magnetic
- A plank with a box on it at one end is gradually raised about the other end.
Topics: Electronic Devices
(124)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two positive ions, each carrying a charge q, are separated by a distance d
- A particle moves along the x-axis from x=0 to x=5 m under the influence of a force
- An ideal heat engine works between temperature T₁=500 K and T₂=375 K.
- A bar magnet of magnetic moment M is placed at right angles to a magnetic
- A plank with a box on it at one end is gradually raised about the other end.
Topics: Electronic Devices (124)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply