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A common emitter amplifier is designed with n-p-n transistor (α=0.99). The input impedence is 1kΩ and load is 10kΩ. The voltage gain will be
Options
(a) 9900
(b) 99
(c) 9.9
(d) 990
Correct Answer:
990
Explanation:
Voltage gain = β × Resistance gain
β = α/(1-α) = 0.99 / (1-0.99) = 99
Resistance gain = (10 × 10³) = 10
Voltage gain = 99 × 10 = 990
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Topics: Electronic Devices
(124)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Time period of the rotation of the earth about its own axis is 24 hour
- Water rises to a height h in capillary tube. If the length of capillary tube above
- A paramagnetic sample shows a net magnetisation of 0.8 Am⁻¹, when placed
- The mean distance between the atoms of iron is 3 x 10⁻¹⁰ m and interatomic force
- In Moseley’s law √ν=a(z-b), the values of the screening constant for K-series
Topics: Electronic Devices (124)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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