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A common emitter amplifier is designed with n-p-n transistor (α=0.99). The input impedence is 1kΩ and load is 10kΩ. The voltage gain will be
Options
(a) 9900
(b) 99
(c) 9.9
(d) 990
Correct Answer:
990
Explanation:
Voltage gain = β × Resistance gain
β = α/(1-α) = 0.99 / (1-0.99) = 99
Resistance gain = (10 × 10³) = 10
Voltage gain = 99 × 10 = 990
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Topics: Electronic Devices
(124)
Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A spherical body of emissivity e=0.6, placed inside a perfectly black body is maintained
- The ratio of the weight of a man in a stationary lift and when it is moving downwards
- During mean life of a radioactive element, the fraction that disintegrates is
- The wetability of a surface by a liquid depends primarily on
- A 1m long wire of diameter 0.31 mm has a resistance of 4.2Ω. If it is replaced by
Topics: Electronic Devices (124)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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