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A common emitter amplifier is designed with n-p-n transistor (α=0.99). The input impedence is 1kΩ and load is 10kΩ. The voltage gain will be
Options
(a) 9900
(b) 99
(c) 9.9
(d) 990
Correct Answer:
990
Explanation:
Voltage gain = β × Resistance gain
β = α/(1-α) = 0.99 / (1-0.99) = 99
Resistance gain = (10 × 10³) = 10
Voltage gain = 99 × 10 = 990
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Topics: Electronic Devices
(124)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The cylindrical tube of a spray pump has radius R, one end of which has n fine holes,
- A battery of e.m.f. E and internal resistance r is connected to an external resistance
- During an adiabatic process, the cube of the pressure is found to be inversely
- Excitation energy of a hydrogen like ion, in its first excitation state, is 40.8 eV.
- Which of the following atoms has the lowest ionisation potential?
Topics: Electronic Devices (124)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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