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A common emitter amplifier has a voltage gain of 50, an input impedance of 100Ω and an output impedance of 200Ω. The power gain of the amplifier is
Options
(a) 500
(b) 1000
(c) 1250
(d) 50
Correct Answer:
1250
Explanation:
Power gain = voltage gain x current gain
= Vₕ . Iₕ = V₀ / Vᵢ . I₀ / Iᵢ
= V₀² / Vᵢ² . Rᵢ / R₀ = 50 x 50 x 100/200
= 2500 / 2 = 1250
Related Questions: - According to photon theory of light which of the following physical quantities,
- The pair of quantities having same dimensions is
- A point source emits sound equally in all directions in a non-absorbing medium.
- Light of wavelength 500 nm is incident on a metal with work function 2.28 eV.
- The maximum particle velocity in a wave motion is half the wave velocity.
Topics: Electronic Devices
(124)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- According to photon theory of light which of the following physical quantities,
- The pair of quantities having same dimensions is
- A point source emits sound equally in all directions in a non-absorbing medium.
- Light of wavelength 500 nm is incident on a metal with work function 2.28 eV.
- The maximum particle velocity in a wave motion is half the wave velocity.
Topics: Electronic Devices (124)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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