| ⇦ | 
| ⇨ |
A charged particle with a velocity 2×10³ ms⁻¹ passes undeflected through electric field and magnetic fields in mutually perpendicular directions. The magnetic field is 1.5T. The magnitude of electric field will be
Options
(a) 1.5×10³ NC⁻¹
(b) 2×10³ NC⁻¹
(c) 3×10³ NC⁻¹
(d) 1.33×10³ NC⁻¹
Correct Answer:
3×10³ NC⁻¹
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - If two vectors 2i+3j+k and -4i-6j-λk are parallel to each other, then the value of λ is
- Water flows through a pipe. The area of cross-section at one place A₁=10 cm²,
- The electron of a hydrogen atom revolves round the proton in a circular
- A cord is wound round the circumference of wheel of radius
- The angular velocity of second’s hand of a watch is
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If two vectors 2i+3j+k and -4i-6j-λk are parallel to each other, then the value of λ is
- Water flows through a pipe. The area of cross-section at one place A₁=10 cm²,
- The electron of a hydrogen atom revolves round the proton in a circular
- A cord is wound round the circumference of wheel of radius
- The angular velocity of second’s hand of a watch is
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Using v=EB,
we have , E = v B
E =(2×103)1.5
E =3×103NC−1