| ⇦ | 
| ⇨ |
A charged particle with a velocity 2×10³ ms⁻¹ passes undeflected through electric field and magnetic fields in mutually perpendicular directions. The magnetic field is 1.5T. The magnitude of electric field will be
Options
(a) 1.5×10³ NC⁻¹
(b) 2×10³ NC⁻¹
(c) 3×10³ NC⁻¹
(d) 1.33×10³ NC⁻¹
Correct Answer:
3×10³ NC⁻¹
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - When a ball is thrown up vertically with velocity vₒ,it reaches a maximum height
- A certain metallic surface is illuminated with monochromatic light of wavelength
- A nucleus ᴢXᴬ emits an α- particle with velocity v. The recoil speed of the daughter
- Which of the following does not increase regularly?
- When a mass m is attached to a spring, it normally extends by 0.2 m.
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When a ball is thrown up vertically with velocity vₒ,it reaches a maximum height
- A certain metallic surface is illuminated with monochromatic light of wavelength
- A nucleus ᴢXᴬ emits an α- particle with velocity v. The recoil speed of the daughter
- Which of the following does not increase regularly?
- When a mass m is attached to a spring, it normally extends by 0.2 m.
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Using v=EB,
we have , E = v B
E =(2×103)1.5
E =3×103NC−1