| ⇦ | 
| ⇨ |
A charged particle with a velocity 2×10³ ms⁻¹ passes undeflected through electric field and magnetic fields in mutually perpendicular directions. The magnetic field is 1.5T. The magnitude of electric field will be
Options
(a) 1.5×10³ NC⁻¹
(b) 2×10³ NC⁻¹
(c) 3×10³ NC⁻¹
(d) 1.33×10³ NC⁻¹
Correct Answer:
3×10³ NC⁻¹
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A thin wire of resistance 4 ohm is bent to form a circle. The resistance across
- Two thin dielectric slabs of dielectric constants K₁ and K₂, (K₁ < K₂) are inserted
- A bullet of mass m moving with velocity v strikes a block of mass M at rests
- Electromagnets are made of soft iron because soft iron has
- Colours appear on a thin soap film and soap bubbles due to the phenomenon of
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A thin wire of resistance 4 ohm is bent to form a circle. The resistance across
- Two thin dielectric slabs of dielectric constants K₁ and K₂, (K₁ < K₂) are inserted
- A bullet of mass m moving with velocity v strikes a block of mass M at rests
- Electromagnets are made of soft iron because soft iron has
- Colours appear on a thin soap film and soap bubbles due to the phenomenon of
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Using v=EB,
we have , E = v B
E =(2×103)1.5
E =3×103NC−1