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A charged oil drop is suspended in a uniform field at 3×10⁴ V/m so that it neither falls nor rises. The charge on the drop will be (Take the mass of the charge=9.9×10⁻¹⁵ kg and g=10 m/s²)
Options
(a) 3.3×10⁻¹⁸ C
(b) 3.2×10⁻¹⁸ C
(c) 1.6×10⁻¹⁸ C
(d) 4.8×10⁻¹⁸ C
Correct Answer:
3.3×10⁻¹⁸ C
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Minority carriers in a p-type semiconductor are
- A coil of resistance 10 Ω and an inductance 5 H is connected to a 100 volt
- If oxygen has root mean square velocity of C m/s, then root mean square velocity of H
- A simple pendulum has a time period T₁ when on the earth’s surface and T₂ When taken
- A body of mass 2 kg travels according to the law x(t)=pt+qt²+rt³
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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