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A charged oil drop is suspended in a uniform field at 3×10⁴ V/m so that it neither falls nor rises. The charge on the drop will be (Take the mass of the charge=9.9×10⁻¹⁵ kg and g=10 m/s²)
Options
(a) 3.3×10⁻¹⁸ C
(b) 3.2×10⁻¹⁸ C
(c) 1.6×10⁻¹⁸ C
(d) 4.8×10⁻¹⁸ C
Correct Answer:
3.3×10⁻¹⁸ C
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Masses of 3 wires of same metal are in the ratio 1:2:3 and their lengths
- Two masses of 9 g and 6 g are connected with a string which is passing over a frictionless
- For a thermocouple, the neutral temperature is 270⁰C when its cold junction is at 20⁰C.
- Which of the following, is a vector quantity?
- An electric dipole of moment ‘p’ is placed in an elecatric field of intensity ‘E’
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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