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A charged oil drop is suspended in a uniform field at 3×10⁴ V/m so that it neither falls nor rises. The charge on the drop will be (Take the mass of the charge=9.9×10⁻¹⁵ kg and g=10 m/s²)
Options
(a) 3.3×10⁻¹⁸ C
(b) 3.2×10⁻¹⁸ C
(c) 1.6×10⁻¹⁸ C
(d) 4.8×10⁻¹⁸ C
Correct Answer:
3.3×10⁻¹⁸ C
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The horizontal component of earth’s magnetic field at a place is 3×10⁻⁴ T
- Sound waves travel at 350m/s through a warm air and at 3500 m/s through brass
- The position x of a particle with respect to time t along x-axis is given
- An elevator car whose floor to ceiling distance is equal to 2.7m starts
- At what height h above earth, the value of g becomes g/2 (where R=radius of earth)?
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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