| ⇦ | 
| ⇨ |
A charged oil drop is suspended in a uniform field at 3×10⁴ V/m so that it neither falls nor rises. The charge on the drop will be (Take the mass of the charge=9.9×10⁻¹⁵ kg and g=10 m/s²)
Options
(a) 3.3×10⁻¹⁸ C
(b) 3.2×10⁻¹⁸ C
(c) 1.6×10⁻¹⁸ C
(d) 4.8×10⁻¹⁸ C
Correct Answer:
3.3×10⁻¹⁸ C
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A particle with total energy E is moving in a potential energy region U(x)
- Pure Si at 300 k has equal electrons (nₑ) and hole (nh) concentrations
- The surface tension of a liquid is 5 newton per metre. If a film
- A parallel plate capacitor is charged and then isolated. The effect of increasing
- An object of mass 3kg is at rest. Now a force F=6t² i⃗+4t j⃗ is applied on the object
Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle with total energy E is moving in a potential energy region U(x)
- Pure Si at 300 k has equal electrons (nₑ) and hole (nh) concentrations
- The surface tension of a liquid is 5 newton per metre. If a film
- A parallel plate capacitor is charged and then isolated. The effect of increasing
- An object of mass 3kg is at rest. Now a force F=6t² i⃗+4t j⃗ is applied on the object
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply