| ⇦ | 
| ⇨ |
A cell of emf E and internal resistance r supplies current for the same time t through external resistance R₁ and R₂ seperately. If the heat developed in both the cases is the same, then the internal resistance r will be
Options
(a) r=√R₁+R₂
(b) r=√R₁xR₂
(c) r=R₁+R₂/2
(d) r=1/R₁+1/R₂
Correct Answer:
r=√R₁xR₂
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - In a mass spectrometer used for measuring the masses of ions, the ions
- Two coherent sources of different intensities send waves which interfere.
- A proton carrying 1 MeV kinetic energy is moving in a circular path of radius
- If an A.C. mains supply is given to be 220 V, what would be the average e.m.f.
- A solid which is transparent to visible light and whose conductivity increases
Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In a mass spectrometer used for measuring the masses of ions, the ions
- Two coherent sources of different intensities send waves which interfere.
- A proton carrying 1 MeV kinetic energy is moving in a circular path of radius
- If an A.C. mains supply is given to be 220 V, what would be the average e.m.f.
- A solid which is transparent to visible light and whose conductivity increases
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply