| ⇦ |
| ⇨ |
A cell can be balanced against 110 cm and 100 cm of potentiometer wire, respectively with and being short circuited through a resistance of 10Ω. Its internal resistance is
Options
(a) 2.0 ohm
(b) zero
(c) 1.0 ohm
(d) 0.5 ohm
Correct Answer:
1.0 ohm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Under constant pressure, graph between P and 1/V is a
- Two lenses of power 15 D and -3 D are placed in contact.
- A ray enters a glass sphere of refractive index μ=√3 at an angle of incidence of 60⁰
- If two slits in Young’s experiment are 0.4 mm apart and fringe width on a screen
- The equivalent resistance of two resistors connected in series is 6 Ω
Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Under constant pressure, graph between P and 1/V is a
- Two lenses of power 15 D and -3 D are placed in contact.
- A ray enters a glass sphere of refractive index μ=√3 at an angle of incidence of 60⁰
- If two slits in Young’s experiment are 0.4 mm apart and fringe width on a screen
- The equivalent resistance of two resistors connected in series is 6 Ω
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply