⇦ | ⇨ |
A Carnot engine, having an efficiency of η=1/10 as heat engine, is used as a refrigerator. If the work done on the system is 10J, the amount of energy absorbed from the reservoir at lower temperature is
Options
(a) 100 J
(b) 99 J
(c) 90 J
(d) 1 J
Correct Answer:
90 J
Explanation:
Efficiency of carnot engine n = 1 – (T₂ / T₁)
That is, 1 / 10 = 1 – (T₂ / T₁)
⇒ (T₂ / T₁) = 1 – (1 / 10) = 9 / 10 ⇒ (T₁ / T₂) = 10 / 9
.·. w = Q₂ . [(T₁ / T₂) – 1) ⇒ 10 = Q₂ [(10 / 9) – 1]
⇒ 10 = Q₂ (1 / 9) ⇒ Q₂ = 90 J
So, 90 J heat is absorbed at lower temperature.
Related Questions: - Two bodies of mass 1 kg and 3 kg have positive vectors i + 2j + k and -3i -2j + k
- If a magnetic substance is kept in a magnetic field, then which of the following
- Consider a compound slab consisting of two different materials having equal thickness
- A block of 2 kg is kept on the floor. The coefficient of static friction is 0.4
- A particle starting from the origin (0, 0) moves in a straight line in the (x, y) plane
Topics: Thermodynamics
(179)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two bodies of mass 1 kg and 3 kg have positive vectors i + 2j + k and -3i -2j + k
- If a magnetic substance is kept in a magnetic field, then which of the following
- Consider a compound slab consisting of two different materials having equal thickness
- A block of 2 kg is kept on the floor. The coefficient of static friction is 0.4
- A particle starting from the origin (0, 0) moves in a straight line in the (x, y) plane
Topics: Thermodynamics (179)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply