MENU

A Carnot engine, having an efficiency of η=1/10 as heat engine, is used

A Carnot Engine Having An Efficiency Of 110 As Heat Physics Question

A Carnot engine, having an efficiency of η=1/10 as heat engine, is used as a refrigerator. If the work done on the system is 10J, the amount of energy absorbed from the reservoir at lower temperature is

Options

(a) 100 J
(b) 99 J
(c) 90 J
(d) 1 J

Correct Answer:

90 J

Explanation:

Efficiency of carnot engine n = 1 – (T₂ / T₁)
That is, 1 / 10 = 1 – (T₂ / T₁)
⇒ (T₂ / T₁) = 1 – (1 / 10) = 9 / 10 ⇒ (T₁ / T₂) = 10 / 9
.·. w = Q₂ . [(T₁ / T₂) – 1) ⇒ 10 = Q₂ [(10 / 9) – 1]
⇒ 10 = Q₂ (1 / 9) ⇒ Q₂ = 90 J
So, 90 J heat is absorbed at lower temperature.

Related Questions:

  1. In an astronomical telescope in normal adjustment a straight black line of length
  2. A lead bullet of 10 gm travelling at 300 m/s strikes against a block
  3. For an ideal gas of diatomic molecules
  4. The ionization energy of Li⁺⁺ is equal to
  5. The half-life of a radioactive substance is 30 min. The time (in minutes) taken

Topics: Thermodynamics (179)
Subject: Physics (2479)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*