| ⇦ | 
| ⇨ |
A Carnot engine, having an efficiency of η=1/10 as heat engine, is used as a refrigerator. If the work done on the system is 10J, the amount of energy absorbed from the reservoir at lower temperature is
Options
(a) 100 J
(b) 99 J
(c) 90 J
(d) 1 J
Correct Answer:
90 J
Explanation:
Efficiency of carnot engine n = 1 – (T₂ / T₁)
That is, 1 / 10 = 1 – (T₂ / T₁)
⇒ (T₂ / T₁) = 1 – (1 / 10) = 9 / 10 ⇒ (T₁ / T₂) = 10 / 9
.·. w = Q₂ . [(T₁ / T₂) – 1) ⇒ 10 = Q₂ [(10 / 9) – 1]
⇒ 10 = Q₂ (1 / 9) ⇒ Q₂ = 90 J
So, 90 J heat is absorbed at lower temperature.
Related Questions: - A rectangular coil of length 0.12 m and width 0.1 m having 50 turns of wire
- A solid cylinder of mass M and radius R rolls without slipping down and inclined plane
- In an inductor when current changes from 2 A to 18 A in 0.05 sec, the e.m.f. induced
- Which one of the following equations of motion represents simple harmonic motion?
- The length of an elastic string is a metre when the longitudinal tension is 4N and b
Topics: Thermodynamics
(179)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A rectangular coil of length 0.12 m and width 0.1 m having 50 turns of wire
- A solid cylinder of mass M and radius R rolls without slipping down and inclined plane
- In an inductor when current changes from 2 A to 18 A in 0.05 sec, the e.m.f. induced
- Which one of the following equations of motion represents simple harmonic motion?
- The length of an elastic string is a metre when the longitudinal tension is 4N and b
Topics: Thermodynamics (179)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply