| ⇦ |
| ⇨ |
A body takes 5 minute for cooling from 50⁰C to 40⁰C. Its temperature comes down to 33.33⁰C in next 5 minute. Temperature of surroundings is
Options
(a) 15⁰C
(b) 20⁰C
(c) 25⁰C
(d) 10⁰C
Correct Answer:
20⁰C
Explanation:
Apply Newton’s law of cooling
In first case, (50 – 40)/5 = K [(50+40)/2 – θ]
⇒ 2 = K [45 – θ] ——(i)
In second case, take 33.33 = 33 x (1/3) = 100/3
[40 – (100/3)]/5 = K {[40 + (100/3)/2] – θ}
⇒ 20/(5×3) = K [(110/3) – θ] ——(ii)
(i)/(ii) = (2 x 5 x 3)/20 = (45 – θ) / [(110/3) – θ]
⇒ 3/2 = (45 – θ) / [(110/3) – θ]
= 110 – 30 = 90 – 20 ⇒ θ = 20⁰C.
Related Questions: - A soap bubble oscillates with time period T, which in turn depends on the pressure
- A proton is moving in a uniform magnetic field B in a circular path of radius a
- A body is thrown vertically upward in air when air resistance is taken into account
- Two capacitors of 10pF and 20pF are connected to 200V and 100V sources, respectively.
- Which of the following is a vector quantity?
Topics: Properties of Bulk Matter
(130)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A soap bubble oscillates with time period T, which in turn depends on the pressure
- A proton is moving in a uniform magnetic field B in a circular path of radius a
- A body is thrown vertically upward in air when air resistance is taken into account
- Two capacitors of 10pF and 20pF are connected to 200V and 100V sources, respectively.
- Which of the following is a vector quantity?
Topics: Properties of Bulk Matter (130)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply