| ⇦ |
| ⇨ |
A body of weight W newton is at the surface of the earth. Its weight at a height equal to half the radius of the earth will be
Options
(a) W/2
(b) 2W/3
(c) 4W/9
(d) 8W/27
Correct Answer:
4W/9
Explanation:
Let h=height above the earth
R=Radius of earth
Now, the acceleration due to gravity at a height ‘h’ above the earth’s surface(g) is given by
gh=g(1+h/R)⁻²
Given h=R/2
gh=g(1+R/2/R)⁻²
gh/g=1/(1+1/2)²=1/(3/2)²=(2/3)²=4/9
since g=W; gh=4/9g;4/9 W.
.
Related Questions: - The acceleration of an electron in an electric field of magnitude 50 V/cm,
- 4 point charges each +q is placed on the circumference of a circle
- An engine pumps water through a hose pipe. Water passes through the pipe
- The first line in Lyman series has wavelength λ. The wavelength
- If the dipole moment of a short bar magnet is 1.25 A-m², the magnetic field on its
Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The acceleration of an electron in an electric field of magnitude 50 V/cm,
- 4 point charges each +q is placed on the circumference of a circle
- An engine pumps water through a hose pipe. Water passes through the pipe
- The first line in Lyman series has wavelength λ. The wavelength
- If the dipole moment of a short bar magnet is 1.25 A-m², the magnetic field on its
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply