| ⇦ | 
| ⇨ |
A body of weight W newton is at the surface of the earth. Its weight at a height equal to half the radius of the earth will be
Options
(a) W/2
(b) 2W/3
(c) 4W/9
(d) 8W/27
Correct Answer:
4W/9
Explanation:
Let h=height above the earth
R=Radius of earth
Now, the acceleration due to gravity at a height ‘h’ above the earth’s surface(g) is given by
gh=g(1+h/R)⁻²
Given h=R/2
gh=g(1+R/2/R)⁻²
gh/g=1/(1+1/2)²=1/(3/2)²=(2/3)²=4/9
since g=W; gh=4/9g;4/9 W.
.
Related Questions: - The phase difference between two points seperated by 0.8 m in a wave of frequency
- Two slits in Young’s experiment have widths in the ratio 1:25. The ratio of intensity
- With the decrease of current in the primary coil from 2 amperes to zero value
- The displacement of a particle along the x-axis is given by x = a sin² ?t
- A charged particle experiences magnetic force in the presence of magnetic field.
Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The phase difference between two points seperated by 0.8 m in a wave of frequency
- Two slits in Young’s experiment have widths in the ratio 1:25. The ratio of intensity
- With the decrease of current in the primary coil from 2 amperes to zero value
- The displacement of a particle along the x-axis is given by x = a sin² ?t
- A charged particle experiences magnetic force in the presence of magnetic field.
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply