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A body of mass M hits normally a rigid wall with velocity V and bounces back with the same velocity. The impulse experienced by the body is
Options
(a) MV
(b) 1.5 MV
(c) 2MV
(d) zero
Correct Answer:
2MV
Explanation:
Impulse experienced by the body
= change in momentum
MV – ( – MV) = 2 MV
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A transistor is working in common emitter mode. Its amplification factor is 80
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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