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A body of mass M hits normally a rigid wall with velocity V and bounces back with the same velocity. The impulse experienced by the body is
Options
(a) MV
(b) 1.5 MV
(c) 2MV
(d) zero
Correct Answer:
2MV
Explanation:
Impulse experienced by the body
= change in momentum
MV – ( – MV) = 2 MV
Related Questions: - The fundamental frequency of a closed organ pipe of length 20 cm is equal to the second
- In common base circuit of a transistor, current amplification factor is 0.95.
- Radius of first orbit of the electron in a hydrogen atom is 0.53 Å. So the radius
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The fundamental frequency of a closed organ pipe of length 20 cm is equal to the second
- In common base circuit of a transistor, current amplification factor is 0.95.
- Radius of first orbit of the electron in a hydrogen atom is 0.53 Å. So the radius
- Monochromatic radiation emitted when electron on hydrogen atom
- The horizontal and vertical components of earth’s magnetic field at a place
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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