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A body of mass M hits normally a rigid wall with velocity V and bounces back with the same velocity. The impulse experienced by the body is
Options
(a) MV
(b) 1.5 MV
(c) 2MV
(d) zero
Correct Answer:
2MV
Explanation:
Impulse experienced by the body
= change in momentum
MV – ( – MV) = 2 MV
Related Questions: - A circuit area 0.01 m² is kept inside a magnetic field which is normal to its plane.
- Three fourth of the active material decays in a radioactive sample in 3/4 sec
- The electric field associated with an e.m. wave in vacuum is given by
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A circuit area 0.01 m² is kept inside a magnetic field which is normal to its plane.
- Three fourth of the active material decays in a radioactive sample in 3/4 sec
- The electric field associated with an e.m. wave in vacuum is given by
- The work done in which of the following processes is zero?
- Given A=4i+6j and B=2i+3j. Which of the following is correct?
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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