| ⇦ | 
| ⇨ |
A body of mass 2 kg travels according to the law x(t)=pt+qt²+rt³,where p=3 m/s,q=4 m/s² and r=5 m/s³.The force acting on the body at t=2 s is
Options
(a) 136 N
(b) 134 N
(c) 158 N
(d) 68 N
Correct Answer:
136 N
Explanation:
m = 2 kg, x = pt + qt² + rt³
⇒ dx/dt = p + 2qt + 3rt²
d²x/dt² = 2q + 6rt = acceleration(a)
At t=2s,
a = 2q +12r = 2 x 4 + 12 x 5
= 68 m/s²
F=ma = 2 x 68 = 136 N.
Related Questions: - If the kinetic energy of the particle is increased to 16 times its previous value
- One-fourth length of a spring of force constant K is cut away. The force constant
- If in an experiment for determination of velocity of sound by resonance tube
- A projectile is fired from the surface of the earth with a velocity of 5 m s⁻¹ and angle
- When a sound wave of wavelength λ is propagating in a medium,
Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If the kinetic energy of the particle is increased to 16 times its previous value
- One-fourth length of a spring of force constant K is cut away. The force constant
- If in an experiment for determination of velocity of sound by resonance tube
- A projectile is fired from the surface of the earth with a velocity of 5 m s⁻¹ and angle
- When a sound wave of wavelength λ is propagating in a medium,
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply