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A body of mass 1.0 kg is falling with an acceleration of 10 ms⁻². Its apparent weight will be (g=10 ms⁻²)
Options
(a) 1.0 kg wt
(b) 2.0 kg wt
(c) zero
(d) 0.5 kg wt
Correct Answer:
zero
Explanation:
R = m (g – a) = m (10 – 10) = zero
This answer is an extension of the lift problem. Actually mg is the force acting on the mass m. As potential energy decreases, its kinetic energy increases as experienced. The question is not correct.
Related Questions: - If the r.m.s. velocity of a gas is v, then
- Wavefront is the locus of all points, where the particles of the medium
- An electron of mass Mₑ, initially at rest, moves through a certain distance in a uniform
- A particle of mass 1mg has the same wavelength as an electron moving with a velocity
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e=300 sin[(100 π)t] V
Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If the r.m.s. velocity of a gas is v, then
- Wavefront is the locus of all points, where the particles of the medium
- An electron of mass Mₑ, initially at rest, moves through a certain distance in a uniform
- A particle of mass 1mg has the same wavelength as an electron moving with a velocity
- An alternating emf given by equation e=300 sin[(100 π)t] V
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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