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A body of mass 1.0 kg is falling with an acceleration of 10 ms⁻². Its apparent weight will be (g=10 ms⁻²)
Options
(a) 1.0 kg wt
(b) 2.0 kg wt
(c) zero
(d) 0.5 kg wt
Correct Answer:
zero
Explanation:
R = m (g – a) = m (10 – 10) = zero
This answer is an extension of the lift problem. Actually mg is the force acting on the mass m. As potential energy decreases, its kinetic energy increases as experienced. The question is not correct.
Related Questions: - In the Young’s double slit experiment, a point P on the central bright fringe
- A body of mass m slides down an incline and reaches the bottom
- For non-conductors, the energy gap is
- Parsec is the unit of
- Find the right condition(s) for Fraunhofer diffraction due to a single slit.
Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In the Young’s double slit experiment, a point P on the central bright fringe
- A body of mass m slides down an incline and reaches the bottom
- For non-conductors, the energy gap is
- Parsec is the unit of
- Find the right condition(s) for Fraunhofer diffraction due to a single slit.
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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