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A body of mass 1.0 kg is falling with an acceleration of 10 ms⁻². Its apparent weight will be (g=10 ms⁻²)
Options
(a) 1.0 kg wt
(b) 2.0 kg wt
(c) zero
(d) 0.5 kg wt
Correct Answer:
zero
Explanation:
R = m (g – a) = m (10 – 10) = zero
This answer is an extension of the lift problem. Actually mg is the force acting on the mass m. As potential energy decreases, its kinetic energy increases as experienced. The question is not correct.
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- At a given temperature the root mean square velocities of oxygen and hydrogen
- Surface tension of a solution is 30 x 10⁻² N/m. The radius of the soap bubble is 5 cm
- A spring balance is attched to the ceiling of lift.A man hangs his bag on the string
- An artificial satellite is revolving round the earth in a circular orbit. Its velocity
- If the cold junction of a thermo-couple is kept at 0⁰C and the hot junction is kept
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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