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A block of mass 10 kg is moving in X-direction with a constant speed of 10 ms⁻¹.It is subjected to a retarding force F=-0.1 x m⁻¹, during its travel from x=20m to x=30m.Its final kinetic energy will be
Options
(a) 475 j
(b) 450 j
(c) 275 j
(d) 250 j
Correct Answer:
475 j
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Work Energy and Power
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The frequencies of X-rays,γ-rays and ultraviolet rays are respectively p,q and r
- A nucleus at rest splits into two nuclear parts having radii in the ratio 1:2.
- The ratio of the weight of a man in a stationary lift and when it is moving downwards
- The drive shaft of an automobile rotates at 3600 rpm and transmits 80 HP
- A thin circular ring of mass M and radius R rotates about an axis through its centre
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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a=0.1x/m
=0.1/10=0.01 m/s2
v2=100-0.01[30×30-20×20]
=100-0.01×500
=100-5=95
final kinetic energy =1/2x10x95
=475J