| ⇦ | 
| ⇨ |
A block of mass 10 kg is moving in X-direction with a constant speed of 10 ms⁻¹.It is subjected to a retarding force F=-0.1 x m⁻¹, during its travel from x=20m to x=30m.Its final kinetic energy will be
Options
(a) 475 j
(b) 450 j
(c) 275 j
(d) 250 j
Correct Answer:
475 j
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A short linear object of length L lies on the axis of a spherical mirror of focal
- The momentum of a body is increased by 20%.The percentage increases in kinetic energy
- A point source emits sound equally in all directions in a non-absorbing medium.
- An object placed at 20 cm in front of a concave mirror produces three times
- The first line in Lyman series has wavelength λ. The wavelength
Topics: Work Energy and Power
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A short linear object of length L lies on the axis of a spherical mirror of focal
- The momentum of a body is increased by 20%.The percentage increases in kinetic energy
- A point source emits sound equally in all directions in a non-absorbing medium.
- An object placed at 20 cm in front of a concave mirror produces three times
- The first line in Lyman series has wavelength λ. The wavelength
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
a=0.1x/m
=0.1/10=0.01 m/s2
v2=100-0.01[30×30-20×20]
=100-0.01×500
=100-5=95
final kinetic energy =1/2x10x95
=475J