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A block of mass 10 kg is moving in X-direction with a constant speed of 10 ms⁻¹.It is subjected to a retarding force F=-0.1 x m⁻¹, during its travel from x=20m to x=30m.Its final kinetic energy will be
Options
(a) 475 j
(b) 450 j
(c) 275 j
(d) 250 j
Correct Answer:
475 j
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Work Energy and Power
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Charge q is uniformly spread on a thin ring of radius R. The ring rotates
- In the diffraction pattern of a single slit
- In common base circuit of a transistor, current amplification factor is 0.95.
- A resistor 30Ω, inductor of reactance 10 Ω and capacitor of reactance 10 Ω
- In the series resonance the value of impedence is 3 Ω and the resistance is 4Ω,
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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a=0.1x/m
=0.1/10=0.01 m/s2
v2=100-0.01[30×30-20×20]
=100-0.01×500
=100-5=95
final kinetic energy =1/2x10x95
=475J