| ⇦ |
| ⇨ |
A block of 2 kg is kept on the floor. The coefficient of static friction is 0.4. If a force F of 2.5 newton is applied on the block, the frictional force between the block and the floor will be
Options
(a) 2.5 N
(b) 5 N
(c) 10 N
(d) 7.84 N
Correct Answer:
2.5 N
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - When you move from equator to pole, the value of acceleration due to gravity (g)
- The charge flowing through a resistance R varies with time t as Q=at-bt²,
- A thin circular ring of mass M and radius R rotates about an axis through its centre
- A spherical liquid drop of radius R is divided into 8 equal droplets. If the surface
- The radius of a nucleus of mass number A is directly proportional to
Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When you move from equator to pole, the value of acceleration due to gravity (g)
- The charge flowing through a resistance R varies with time t as Q=at-bt²,
- A thin circular ring of mass M and radius R rotates about an axis through its centre
- A spherical liquid drop of radius R is divided into 8 equal droplets. If the surface
- The radius of a nucleus of mass number A is directly proportional to
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply