| ⇦ |
| ⇨ |
A black body is at 727⁰C. It emits energy at a rate which is proportional to
Options
(a) (1000)⁴
(b) (1000)²
(c) (727)⁴
(d) (727)²
Correct Answer:
(1000)⁴
Explanation:
According to Stefan’s law, E α T⁴
E α (t + 273)⁴ K [723⁰C = (727 + 273)K]
E α (727 + 273)⁴ K
E α (1000)⁴ K
Related Questions: - The binding energy of deutron is 2.2 MeV and that of ₂⁴He is 28 MeV.
- A horizontal straight conductor kept in north-south direction falls under gravity. Then
- During mean life of a radioactive element, the fraction that disintegrates is
- An electron is moving in a circular path under the influence of a transverse magnetic
- A lift is moving down with acceleration a.A man in the lift drops a ball
Topics: Properties of Bulk Matter
(130)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The binding energy of deutron is 2.2 MeV and that of ₂⁴He is 28 MeV.
- A horizontal straight conductor kept in north-south direction falls under gravity. Then
- During mean life of a radioactive element, the fraction that disintegrates is
- An electron is moving in a circular path under the influence of a transverse magnetic
- A lift is moving down with acceleration a.A man in the lift drops a ball
Topics: Properties of Bulk Matter (130)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply