| ⇦ | 
| ⇨ |
A beam of light contains two wavelengths 6500Å and 5200Å. They form interference fringes in Young’s double slit experiment. What is the least distance (approx) from central maximum, where the bright fringes due to both wavelength coincide? The distance between the slits is 2 mm and the distance of screen is 120 cm.
Options
(a) 0.16 cm
(b) 0.32 cm
(c) 0.48 cm
(d) 1.92 cm
Correct Answer:
0.16 cm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A uranium nucleus ₉₂ U ²³⁸ emits an α-particle and a β-particle in succession.
- The value of Poisson’s ratio lies between
- Huygen’s wave theory could not explain
- Light is emitted when
- Two point white dots are 1 mm apart on a black paper.
Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A uranium nucleus ₉₂ U ²³⁸ emits an α-particle and a β-particle in succession.
- The value of Poisson’s ratio lies between
- Huygen’s wave theory could not explain
- Light is emitted when
- Two point white dots are 1 mm apart on a black paper.
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply