| ⇦ | 
| ⇨ |
A beam of light contains two wavelengths 6500Å and 5200Å. They form interference fringes in Young’s double slit experiment. What is the least distance (approx) from central maximum, where the bright fringes due to both wavelength coincide? The distance between the slits is 2 mm and the distance of screen is 120 cm.
Options
(a) 0.16 cm
(b) 0.32 cm
(c) 0.48 cm
(d) 1.92 cm
Correct Answer:
0.16 cm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions:
- On a frictionless surface, a block of mass M moving at speed v collides elastically
- Four identical rods are joined to from a square. If the temperature difference
- The radius of a nucleus of mass number A is directly proportional to
- Temperature is a measurement of coldness or hotness of an object.
- A spherical drop of capacitance 1μF is broken into eight drops of equal radius.
Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply